7/10x + 1y 630 (hours) raw subdivision --------- 1 1/2x + 5/6y 600 (hours) Sewing department --------- 2 x + 2/3y 708(hours) finishing department --------- 3 1/10x + 1/4y ? 135 (hours) promotional material department --------- 4 x ? 0 and y ? 0 assumption 2: Non-negativity constraint Assumption 3: All variables are continuous 5.Solution: fuck off graph, identify FR, mark landmark points and enter profit at all corner points and postulate maximum. optimum sol: (540, 252); =7,668 6.2nd Method (Optional): Convert obj.fn into standard hammer (y = mx + c); y = -10/9x + /9 Draw family of parallel lines with 10/9 as slope. Highest line within the feasible share will give you optimal point. [Note need to teach this method] 7. unloose: Un-utilized resource LHS = Utilization (U) and RHS = Availability (A) U + S = A (add tantalize up on LHS and variation will be seminal fluid equality) 7/10x + y + S1 = 630 1/2x + 5/6y + S2 = 600...If you want to get a full essay, position it on our website: Ordercustompaper.com
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